Let’s assume iterator B is currently positioned on 50, and iterator A is positioned on 100. In order to determine if 100 is in B, we have to advance B to 10000 . This can be an expensive operation because advancing to the next match may require scanning several blocks containing values between 50 and 10000.
So how did I fix it. Well, basically I handed the entire profile name to the SDK loader by passing .profile_name() and let it do a full profile load. Oh and this made the function way shorter:，详情可参考新收录的资料
，这一点在新收录的资料中也有详细论述
function empty(): Tree {，更多细节参见新收录的资料
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